3.3x^2-2x=27

Solution for 3.3x^2-2x=27 equation:

3.3x^2-2x=27

We move all terms to the left:

3.3x^2-2x-(27)=0

a = 3.3; b = -2; c = -27;
Δ = b2-4ac
Δ = -22-4·3.3·(-27)
Δ = 360.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{360.4}}{2*3.3}=\frac{2-\sqrt{360.4}}{6.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{360.4}}{2*3.3}=\frac{2+\sqrt{360.4}}{6.6}
$